Question: What is the percent of the unprotonated form of ammonia (Kb NH3 = 1.74 x 10-5) in a solution at pH 8.68? What is the percent of the unprotonated form of ammonia ( Kb NH 3 = 1 . 7 4 x 1 0 - 5 ) in a solution at pH
8. Use the Henderson-Hasselbalch equation to calculate the pH of each solution. a solution that ikb for nh3s 0.18 M in HCHO2 and 0.12 M in NaCHO2 (Ka(HCHO2)=1.8×10−4) Express your answer to two decimal places. Part B a solution that is 0.14 M in NH3 and 0.20 M in NH4Cl (Kb(NH3)=1.76×10−5) Express your answer to two decimal places. 3.
calculate the pH of the following solutions: 1) 0.40 M NH4ClO4 Kb(NH3)=1.8x10-5 2) 0.45 M NaOCl Ka(HOCl)=3.5x10-8 Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on.
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kb for nh3|Solved Determine the pH of (a) a 0.10 M NH3
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